Question

What is the solubility of silver sulfate in water in g/L of water? (Ksp= 1.2 x 10–5)

Answer 1

ICE table

	Ag2SO4-->	2Ag+	SO42-
I		0	0
C	-x	+2x	+x
E		2x	x

Solubility of Ag2SO4 can be represented by following equation

Ag2SO4 --> 2Ag+ + SO42-
solubility product;

Ksp = [Ag+]^2.[SO42-]

  
Use ICE table , equilibrium concentration
Ksp = (2x)^2.(x)2

Ksp = 4x^3
1.2 x10^-5 = 4x^3

x= 0.01442249 mols/L

This is molar solubility of Ag2SO4 .To convert it in to g/L multiply
the number with molar mass of Ag2SO4

1.442249 x10^-2 mol/L *311.799 g/mol = 4.496 g/L

answered by: anonymous