Question

# What is the pH of a solution made by mixing 30.00 mL of 0.10 M acetic...

What is the pH of a solution made by mixing 30.00 mL of 0.10 M acetic acid with 50.00 mL of 0.100 M KOH? Assume that the volumes of the solutions are additive. Ka = 1.8 × 10-5 for CH3CO2H.

Given:
M(CH3COOH) = 0.1 M
V(CH3COOH) = 30 mL
M(KOH) = 0.1 M
V(KOH) = 50 mL

mol(CH3COOH) = M(CH3COOH) * V(CH3COOH)
mol(CH3COOH) = 0.1 M * 30 mL = 3 mmol

mol(KOH) = M(KOH) * V(KOH)
mol(KOH) = 0.1 M * 50 mL = 5 mmol

We have:
mol(CH3COOH) = 3 mmol
mol(KOH) = 5 mmol

3 mmol of both will react

excess KOH remaining = 2 mmol
Volume of Solution = 30 + 50 = 80 mL
[OH-] = 2 mmol/80 mL = 0.025 M

use:
pOH = -log [OH-]
= -log (2.5*10^-2)
= 1.60

use:
PH = 14 - pOH
= 14 - 1.60
= 12.40

#### Earn Coins

Coins can be redeemed for fabulous gifts.

##### Need Online Homework Help?

Most questions answered within 1 hours.

##### Active Questions
• Determine whether each of the following scenarios is a regression, classification, or clustering problem. We run...
• A car makes a trip along a straight line without changing direction. The average speed of...
• What were the major differences during the reconstruction era between the northern and southern parts of...
• A group of researchers want to determine whether the order in which items are presented influences...
• A scientist wishes to perform the Stern-Gerlach experiment to separate silver atoms at least 1cm (greater...
• You are conducting a study to see if the mean doctor's salary (in thousands of dollars)...