If a solution containing 98.867 g of mercury(II) acetate is allowed
to react completely with a solution containing 17.796 g of sodium
sulfide, how many grams of solid precipitate will be formed?
How many grams of the reactant in excess will remain after the
reaction?
Mercury(II) acetate and sodium sulfide have molar masses of
318.7 g/mol and 78 g/mol respectively.
Mercury(II) sulfide has molar mass of 232.7 g/mol
respectively.
Number of moles of mercury(II) acetate
Number of moles of sodium sulfide
Number of moles of mercury(II) sulfide formed 0.228
Mass of mercury(II) sulfide formed
The moles of the reactant in excess (mercury(II) acetate) will
remain after the reaction are
The grams of the reactant in excess (mercury(II) acetate) will
remain after the reaction are
Get Answers For Free
Most questions answered within 1 hours.