A sample of an oxide of antimony (Sb) contained 30.0g of antimony combined with 9.8g of oxygen. The simplest formula for the oxide is...?
Sb2O5
Explanation
Mass of Antimony = 30.g
Molar mass of Antiminy = 121.760g/mol
No of mole of Antimony = 30.g/121.760g/mol =0.2464mol
Mass of Oxygen = 9.8g
Molar mass of Oxygen = 16g/mol
No of mole of Oxygen = 9.8g/16g/mol = 0.6125
Divide each mole by lowest of them
Oxygen : 0.6125/0.2464 = 2.49
Antimony : 0.2464/0.2464 = 1
multiply the above reuslt by 2 to make whole No
Oxygen : 2.49 ×2 = 5
Antimony : 1×2 = 2
So, the simplest formula for Antimony oxide is Sb2O5
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