Question

if according to the following reaction, how much (in grams) of water vapor can you expect if 4.50 grams of O2 reacts completely?

2 H2(g) +O2(g) --> H2O(g)

Answer 1

given reaction is

2H2 + O2 ------------> H2O(at first we have to balance the equation)

now balanced equation is -

2H2 + O2---------------------> 2H2O

now mole of oxygen = mass / molar mass , molar mass of oxygen is 32 g

= 4.50/32 = 0.140625 mole

now observe the reaction (balanced) that 1 mole of O2 reacts and produces 2 mole of water so,

0.140625 mole will react and give 0.140625*2 mole of water vapours = 0.28125 mole

molecular mass of water is 18 .

total mass = 18*0.28125 = 5.0625 g of water .............

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