Question

True or False Consider the salt ammonium bicarbonate, NH4HCO3. The Ka of NH4+is 5.6x10-10and the Kb...

True or False

Consider the salt ammonium bicarbonate, NH4HCO3. The Ka of NH4+is 5.6x10-10and the Kb of HCO3-is 2.3x10-8. A solution of this salt is acidic .

TRUE

OR

FALSE

Homework Answers

Answer #1

False

Explanation

Ammonium bicarbonate(NH4HCO3) is the salt made by the reaction between weak base NH3 and weak acid H2CO3.

NH3(aq) + H2CO3(aq) -------> NH4HCO3

The strength of NH3( Kb = 1.8×10-5) is higher than the strength of first dissociation of H2CO3 (Ka1 = 3.16×10-7). So, strength of NH4+ (conjucate acid of NH3, Ka = 5.6×10-10) is lower than the strength of HCO3-( conjucate base of H2CO3 , Kb = 2.3×10-8)

So, base domination in solution and the solution will be basic.

Therefore,

The statement is False

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Soluble salts containing the ammonium ion (NH4+) can give acidic, neutral or basic solutions when dissolved...
Soluble salts containing the ammonium ion (NH4+) can give acidic, neutral or basic solutions when dissolved in water. For any given salt that contains ammonium ion, describe how you would predict whether an aqueous solution of that salt would be acidic, neutral or basic. Note: Kb for the weak base, NH3, is 1.8E-5.
a) why is the bicarbonate solution basic based on Ka and Kb values? b) why is...
a) why is the bicarbonate solution basic based on Ka and Kb values? b) why is the carbonate solution more basic than the bicarbonate solution based on Ka or Kb values?
What is the pH of a 0.240 M solution of ammonium formate (NH4HCOO)? The KA for...
What is the pH of a 0.240 M solution of ammonium formate (NH4HCOO)? The KA for NH4+ is 5.6E-10 and the KB for HCOO- is 5.6E-11.
Determine if the following salt solutions (0.123 M) are basic, acidic or neutral. Determine the pH...
Determine if the following salt solutions (0.123 M) are basic, acidic or neutral. Determine the pH of the solution, if possible. (Ammonium: Ka = 5.8 x 10-10, Sulfate: Kb = 8.3 x 10-13) a. Sodium nitrate b. Sodium sulfate c. Ammonium nitrate d. Ammonium sulfate
1. The Ka for HF is 6.9 x 10-4. What is the value of Kb for...
1. The Ka for HF is 6.9 x 10-4. What is the value of Kb for F-? (Show your calculations) 2. The Kb for NH3 is 1.8 x 10-5. What is the value of Ka for NH4+? (Show your calculations) 3. From what acid and what base were the following salts made and what would you expect the pH of the salt solution to be (> 7, =7 or <7)? Why? Rb3PO4 NH4I  
The salt ammonium nitrate, NH4NO3(s), completely dissociates into NH4+(aq) and NO3−(aq) in an aqueous environment. The...
The salt ammonium nitrate, NH4NO3(s), completely dissociates into NH4+(aq) and NO3−(aq) in an aqueous environment. The NO3−ion has no acid or base properties, but the ammonium ion is the conjugate acid of the weak base, ammonia. Part a. Write a balanced chemical equation showing how the ammonium ion reacts with water to affect the pH of the resulting solution (you can ignore the nitrate ion in your balanced equation). Part b. Find the pH of a 0.100 M solution of...
Given the following values for HC2O4^- (Ka=6.4E-5 and kb=1.7E-13) which reaction from above is favored? Would...
Given the following values for HC2O4^- (Ka=6.4E-5 and kb=1.7E-13) which reaction from above is favored? Would a salt solution of NaHC2O4 be acidic basic or neutral?
Titration Problems A sample of ammonium chloride (NH4Cl, MW = 53.49 g/mol; Ka, NH4 + =...
Titration Problems A sample of ammonium chloride (NH4Cl, MW = 53.49 g/mol; Ka, NH4 + = 5.70 x 10-10) was contaminated with inert material. The whole sample was dissolved in 25.00 mL of water, and this solution was titrated with 12.45 mL of 0.1000 M NaOH to reach the end point. a. Calculate the amount of ammonium chloride present in the sample (in grams). b. What was the pH of the solution at the beginning of the titration (assuming no...
A) HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO...
A) HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.087 M in NaClO at 25 °C? The hint is: Na is a spectator ion in this situation. Start by finding the Kb of ClO–. B) A solution of household bleach contains 5.25% sodium hypochlorite, NaOCl, by mass. Assuming that the density of bleach is the same as water, calculate...
Consider a solution of 2.0 M HCN and 1.0 M NaCN (Ka for HCN = 6.2...
Consider a solution of 2.0 M HCN and 1.0 M NaCN (Ka for HCN = 6.2 x 10-10). Which of the following statements is true? a) The solution is not a buffer because [HCN] is not equal to [CN-] b) The pH will be below 7.00 because the concentration of the acid is greater than that of the base. c) [OH-] > [H+] d) The buffer will be more resistant to pH changes from addition of strong acid than to...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT