A calorimeter contains 30.0 mL of water at 11.5 ∘C . When 2.10 g of X (a substance with a molar mass of 42.0 g/mol ) is added, it dissolves via the reaction
X(s)+H2O(l)→X(aq)
and the temperature of the solution increases to 30.0 ∘C .
Calculate the enthalpy change, ΔH, for this reaction per mole of X.
Assume that the specific heat of the resulting solution is equal to that of water [4.18 J/(g⋅∘C)], that density of water is 1.00 g/mL, and that no heat is lost to the calorimeter itself, nor to the surroundings.
Express the change in enthalpy in kilojoules per mole to three significant figures.
mass of water = density x volume = 30 x 1 = 30 g
total mass of solution = 30+ 2.10 = 32.10 g
dT = 30-11.5 = 18.5 oC
Q = m Cp dT
Q = 32.1 x 4.18 x 18.5 = 2482 J
Q = 2.482 kJ
moles of X = mass /molar mass
= 2.10 /42
= 0.05
ΔH = - Q / n
= 2.482 / 0.05
= - 49.6 kJ / mol
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