Be sure to answer all parts. __________kJ/mol |
Standard enthalpy change in kJ/mol as follows:
Ethane C2H4= +52.47, Hydrogen sulfide H2S is - 52.47 , Sulfur
dioxide SO2 is - 296.84,
Water liquid H2O is - 285.83,Carbon dioxide CO2 is - 393.51 and for
Oxygen O2 is zero.
A]
ΔrH° = C2H4(g) + 3O2(g) →2CO2(g) + 2H2O(l)
ΔrH° = 2·ΔfH°(CO2(g)) + 2 ·ΔfH°(H2O(l)) - ΔfH°(C2H4(g)) - 3 ·ΔfH°(O2(l))
= 2·(-393.52kJ/mol) + 2 ·( -285.83kJ/mol) - (52.47kJ/mol) - 3
·(0kJ/mol)
ΔrH° = 2( - 393.51) + 2( - 285.83) - ( + 52.47) - 0
ΔrH° = - 1411.15 kJ/mol
Reaction is exothermic
B]
2H2S(g) + 3O2(g) →
2H2O(l) + 2SO2(g)
ΔrH° = 2H2O + 2SO2 - 2H2S - 3O2
ΔrH° = 2( - 285.83) + 2( - 296.84) - 2( - 20.63) - 0
ΔrH° = - 1124.08 kJ/mol
Reaction is exothermic
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