Experimental H2O in Alum is 42.34% (given)
Calculate theoretical H2O in Alum
Calculate molar mass of alum (KAl(SO4)2.12H2O)
39.098 + 26.982 + 2(32.06) + 20 (15.999) + 24(1.0079) = 474.3696 g/mol
There are 12 molecules of water in alum
Molar mass H2O = (15.999) + 2(1.0079) = 18.0148
There are 12 molecules of water in alum
Mass of water in alum = 18.0148*12 = 216.1776
% H2O = (216.1776/474.3696)*100 = 45.57%
% error = [(Experimental – theoretical) / theoretical] x 100
= [(42.34 – 45.57)/45.57] x 100 = 7.08 %
Get Answers For Free
Most questions answered within 1 hours.