Question

Consider these half reactions:

A³⁺ + e- --> A²⁺           E^o = 1.70 V

B⁴⁺ + 2e- -->   B²⁺          E^o = 0.50 V

If you mix 50.00 mL of 0.100 M A³⁺ with 50.00mL of 0.100 M B²⁺, what would be the resulting potential of the solution, as measured in volts on a platinum electrode relative to the SHE? Enter your answer below, to two digits after the decimal point. Do not enter units

Answer 1

Let us consider given reaction,

A3⁺ + e- --> A2+           Eo = 1.70 V

B4⁺ + 2e- -->   B2+          Eo = 0.50 V

E⁰_cell = RPC - RPA

= 1.70 - 0.50

= 1.20 V

Let us consider ,

E_cell = E⁰_cell - 0.059 / n x log [B⁴⁺] [A²⁺]² / B²⁺] [A³⁺]²

= 1.20 - 0.059 / 2 x log 0.05 x(0.05)² / 0.05 x(0.05)²

= 1.20 - 0.059 / 2 x log 1

= 1.20 - 0

E_cell = 1.20 V