Given the decomposition of hydrogen peroxide, calculate the
moles of oxygen gas produced from 4.20 mol of H2O2.
2H2O2(l)→2H2O(l)+O2(g)
as the given reaction is
2 H2O2(l)---------> 2 H2O(l) + O2(g)
as we observed the reaction is balanced here ...... in case if reaction is not balanced then we have to balance the reaction at first.
now after observing the balance reaction ,
2 mole of H2O2 decompose and produces 1 mole of O2 . so means when H2O2 decomposes its 1/2 mole of oxygen will produce .
now the mole of oxygen gas produced = 1/2 mole of H2O2
mole of H2O2 = 4.20
so oxygen will produce = 4.20/2 = 2.10 mole .....
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