1) According to the following reaction, how many grams of water are needed to form 22.2 grams of oxygen gas? water (l) hydrogen (g) + oxygen (g) _____ grams water
The chemical reaction to the transformation is
for every two moles of H2, one mole of O2 will be formed. The stoichiometric ratio for the formation of O2 will be 1/2, with respect to water which is the limiting reagents.
molar mass of H2O = 18 g
molar mass of O2 = 32 g
moles of H2O used = 22.2/18 moles = 1.23 moles
The number of moles of O2 formed = 1.23/2 =0.616 moles
grams of O2 formed will be determined by using formula
number of moles formed = grams of O2 formed / Molar mass
so , Mass of O2 formed = 0.616*32 = 19.712 g
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