Explain why C0 = [H+]∞ for the solvolysis reaction of t-butyl chloride and water
t-butyl chloride hydrlysis is a Sn1 type of reacton. The mechanism involves loss of Cl- in the first step which is the rate determining slow step of the reaction. The formed tertiary carbocation is stable and gets solvolyzed in water. The solvolysis is the second step and is performed by the solvent water which is in excess. The second step is the fast step and does not influence the rate of the reaction, making the concentration Co = [H+]inifnity (exces solvent) does not influence rate of the reaction and its concentration remains almost unchanged at all times.
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