Question

1. Answer the following question based on the reaction below: NaOH(aq) + KHP(s) ---> NaKp(aq) +...

1. Answer the following question based on the reaction below:

NaOH(aq) + KHP(s) ---> NaKp(aq) + H2O(l)

A 1.348g sample of impure KHP was titrated with a 0.0942 M solution of NaOh. To completely react the KHP in the sample, 69.34mL of base was needed. KHP (potassium hydrogen phthalate, 204.23 g/mol)

a.)How many grams of KHP were in the unknown sample?

b.) What is the precentage of KHP in the unknown sample?

Homework Answers

Answer #1

NaOH(aq) + KHP(s) ---> NaKp(aq) + H2O(l)

no of moles of NaOH = molarity * volume in L

                                    = 0.0942*0.06934   = 0.00653 moles

1 mmoles of NaOH react with 1 mole of KHP

0.00653 moles of NaOH react with 0.00653 moles of KHP

mass of KHP   = no of moles * gram molar mass

                       = 0.00653*204.23   = 1.334g of KHP

b.

The percentage of KHP in unknown sample   = 1.334*100/1.348   = 98.96%

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of...
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of 0.1 M solution. Calculate how many grams of potassium acid phthalate (KHP, FW = 204.2 g/mol) will react with about 25 ml of the 0.1 M NaOH solution. The reaction is as follows: HKC8H4O4 + NaOH → H2O + NaKC8H4O4 Calculate how many mL of 1 M HCl is needed to make 1 L of 0.2 M HCl. HCl + NaOH → H2O +...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of a 1 M NaOH solution. 2). The mass of potassium hydrogen phthalate (KHP) required to react with 25 mL of a 1 M NaOH solution. The molecular weight of KHP is 204.23 g/mol. 3). The amount of water required to dissolve the quantity of KHP calculated in (b), given that the solubility of KHP is 10.2 grams per liter.
After standardizing your NaOH solution, you have determined that the concentration is actually 0.1125 M. What...
After standardizing your NaOH solution, you have determined that the concentration is actually 0.1125 M. What is the weight percent concentration of KHP (MW=204.23) in your unknown sample of mass 1.625 g if it takes 38.40 mL of titrant to reach the equivalence point? A student weighs out 1.7500 grams of dried potassium hydrogen phthalate standard (MW=204.23) and finds that it takes 39.05 mL to reach the endpoint of the titration with the solution of NaOH. What is the molarity...
[Make sure to do both problems to get a thumbs up] 1. What volume (in mL)...
[Make sure to do both problems to get a thumbs up] 1. What volume (in mL) of 0.08970 M HNO3 is required to react completely with 0.2391 g of potassium hydrogen phosphate? 2 HNO3(aq) + K2HPO4(aq) → H2PO4(aq) + 2 KNO3(aq) 2. Potassium acid phthalate, KHC8H4O4, or KHP, is used in many laboratories, including general chemistry laboratories, to standardize solutions of base. KHP is one of only a few stable solid acids that can be dried by warming and weighed....
Potassium acid phthalate, KHC8H4O4, or KHP, is used in many laboratories, including general chemistry laboratories, to...
Potassium acid phthalate, KHC8H4O4, or KHP, is used in many laboratories, including general chemistry laboratories, to standardize solutions of base. KHP is one of only a few stable solid acids that can be dried by warming and weighed. A 0.3574 g sample of KHC8H4O4 reacts with 34.79 mL of a NaOH solution in a titration. What is the molar concentration of the NaOH? Here is the equation given below. KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l)
Based off info below please answer blank boxes. Thanks! Application Questions: 12. Before using a solution...
Based off info below please answer blank boxes. Thanks! Application Questions: 12. Before using a solution of NaOH as a standard for a titration, its precise concentration must be determined by titration with a standard acid. This is because solid NaOH absorbs water from the atmosphere, so its solid form is difficult to keep free of contaminated H2O. A common acid used for standardization is the acid-salt, potassium hydrogen phthalate (KHP), KHC8H4O4. Another way is to use a standardized solution...
Answer the following for the reaction: NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq) 1.How many milliliters of 0.200M NaOH solution are needed...
Answer the following for the reaction: NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq) 1.How many milliliters of 0.200M NaOH solution are needed to react with 26.0 mL of a 0.420 M NiCl2 solution? 2.How many grams of Ni(OH)2 are produced from the reaction of 48.0 mL of a 1.80 M NaOH solution and excess NiCl2 ? 3.What is the molarity of 30.0 mL of a NiCl2 solution that reacts completely with 11.3 mL of a 0.360 M NaOH solution?
Y2(CO3)3(aq) + HCl(aq) --> YCl3(aq) + CO2(g) + H2O(l) HCl(aq) + NaOH --> NaCl(aq) + H2O(l)...
Y2(CO3)3(aq) + HCl(aq) --> YCl3(aq) + CO2(g) + H2O(l) HCl(aq) + NaOH --> NaCl(aq) + H2O(l) Consider the unbalanced equations above. A 0.283 g sample of impure yttrium carbonate was reacted with 50.0 mL of 0.0965 M HCl. The excess HCl from the first reaction required 5.31 mL of 0.104 M NaOH to neutralize it in the second reaction. What was the mass percentage of yttrium carbonate in the sample?
Use the following information to predict ΔH for the reaction: HClO4(aq) + NaOH(aq) → NaClO4(aq) +...
Use the following information to predict ΔH for the reaction: HClO4(aq) + NaOH(aq) → NaClO4(aq) + H2O(l) Solution Mass (g) Volume (ml) Molarity (mol/L) Initial Temperature (°C) HClO4(aq) 51.99 51.98 0.500 25.42 NaOH(aq) 51.49 51.48 0.500 25.42 The HClO4(aq) solution was poured into a calorimeter with a heat capacity of 115 J/C, and allowed to sit for about 5 minutes. The NaOH(aq) solution was then added, and the temperature rose to 28.16°C. The heat absorbed by the solution/water is _______...
1. Consider the reaction: Cr2O72- (aq) + 14 H+ (aq) + 6 Fe2+ (aq) >>> 2...
1. Consider the reaction: Cr2O72- (aq) + 14 H+ (aq) + 6 Fe2+ (aq) >>> 2 Cr3+ (aq) + 6 Fe3+ (aq) + 7 H2O (l) In the lab, it is found that 19.30 mL of K2Cr2O7 solution is needed to react with 25.00 mL of 0.4000 M Fe2+ (aq) solution, what is the molarity of the potassium dichromate solution?