A compound containing 5.9265% hydrogen and 94.0735% oxygen has a molar mass of 34.01468 g/mol. Determine the empirical and molecular formula for this compound.
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Molecular formula H2O2
Empirical formula HO
Explanation
Mass of Hydrogen = (5.9265/100)× 34.01468g = 2.01588g
Mass of Oxygen = ( 94.0735/100) × 34.01468g = 31.9988g
Molar mass of Hydrogen = 1.00794g/mol
No of mole of Hydrogen = 2.01588g/1.00794(g/mol) = 2
Molar mass of Oxygen = 15.999g/mol
No of mole of Oxygen = 31.9988g/15.999g/mol = 2
Therefore
Molecular formula = H2O2
Empirical formula
ratio of Hydrogen = No of mole of Oxygen /No of mole of Hydrogen = 2/2 =1
ratio of Oxygen = No of mole of Oxygen / No of mole of Hydrogen = 2/2 =1
Therefore,
Empirical formula = HO
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