(10 pts) What is the density of gaseous ammonia (NH3) at 39°C and 1.56 atm?
P = 1.56 atm
T= 39.0 oC
= (39.0+273) K
= 312 K
Molar mass of NH3 = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
Lets derive the equation to be used
we have below equation to be used:
p*V=n*R*T
p*V=(mass/molar mass)*R*T
p*molar mass=(mass/V)*R*T
p*molar mass=density*R*T
Put Values:
1.56 atm *17.034 g/mol = density * 0.08206 atm.L/mol.K *312.0 K
density = 1.038 g/L
Answer: 1.038 g/L
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