What is the molarity of 16.1 grams of lithium hydroxide Dissolved to 200.0 mL of solution?
Here's what I tried:
LiOH 16.1g / 23.95 g/mol= 0.67mol
200ml= 0.2L
0.67mol / 0.2L= 3.36
but my answer is wrong....and I don't know why?
Molarity is defined as the number of moles of solute present in one litre of solutions
i.e Molarity = moles of solute( LiOH)/ volume of Sol. in liter
Here mass of LiOH is given 16.1g we have to find moles.so we divide it by its molar mass which is 23.95 g/mol
So moles= 16.1g÷23.95g/mol = 0.67 mol
Now.l,
Converting volume 200 ml to litre i.e 0.2 L
For molarity we have to divide moles of LiOH with volume of Sol.
Molarity =( 0.67÷0.2 ) mol/L = 3.3 mol/L
Your answer is correct, but if you consider correct significant figures it should be 3.3 mol/L. Also try to give Answer in proper units.
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