Question

A laser pointer used has a frequency of 2.04* 1014 Hz. a. What is the wavelength...

A laser pointer used has a frequency of 2.04* 1014 Hz.

a. What is the wavelength of the light?

b. If 23.7 KJ of energy is given off when pointing at an excited chemical equation on the projector screen, how many photons were emitted?

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Homework Answers

Answer #1

a)

we have:

frequency = 2.04*10^14 s-1

we have below equation to be used:

wavelength = speed of light/frequency

=(3.0*10^8 m/s)/(2.04*10^14 s-1)

= 1.471*10^-6 m

Answer: 1.47*10^-6 m

b)

we have:

frequency = 2.04*10^14 s-1

1st calculate energy of 1 photon

we have:

frequency = 2.04*10^14 s-1

we have below equation to be used:

Energy = Planck constant*frequency

=(6.626*10^-34 J.s)*(2.04*10^14) s-1

= 1.352*10^-19 J

number of photon = total energy/energy of 1 photon

n = 23700.0/1.352*10^-19

= 1.753*10^23

Answer: 1.75*10^23

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