Question

Part E: Osmosis This was a celery experiment, and we had solutions. Someonne answered with the...


Part E: Osmosis

This was a celery experiment, and we had solutions. Someonne answered with the following chart only. My questions is should the percent difference be a negative or do you ignore the negative. See all info below.

7. Complete the table (24 pts: 1 pts per entry)

Copy the molality values of each solution (from Question 1 and Question 5).

Calculate the difference and % difference in the mass of the celery stalk for each solution.  

                 Mass difference = mass (after) − mass (initial)            (negative for loss; positive for gain)

                       %difference =massdifference×100%                                  (negativeforloss; postivie for gain)

mass(initial)

Indicate if the solution was hypertonic, hypotonic, or isotonic.

Solutions

Molality

Initial mass(mi)

Final mass

(mf)

Mas difference

(∆m)

% difference=

(∆m/mi)100

Tonicity

A

2m

4.04g

4.12g

0.08g

1.98%

Hypotonic

B

0.4m

4.47g

3.81g

- 0.66g

14.77%

Hypertonic

C

0.2m

4.92g

4.29g

- 0.63g

   12.80%

Hypertonic

D

0.3m

4.55g

4.15g

- 0.4g

8.79%

Hypertonic

E

1.1m

3.99g

3.73g

- 0.26g

6.51%

Hypotonic

F

0.

3.40g

3.30g

0.10g

2.94%

Hypertonic

Calculations for Solution A:

Initial mass 4.04g

Mass at 2 hours 4.12g

Mass difference = mass (after) – mass (initial) = 4.12-4.04=0.08g

% difference = mass diff/mass ini x 100% = 0.08/4.04 x 100 = 1.98%

Tonicity of solution is Hypotonic

Calculations for Solution B:

Initial mass 4.74g

Mass at 2 hours 3.81g

Mass difference = mass (after) – mass (initial) = 3.81-4.47=-0.08g

% difference = mass diff/mass ini x 100% = -0.66/4.47 x 100 = -14.76%

Tonicity of solution is Hypertonic

Homework Answers

Answer #1

Answer is yes u are suppose to get a negative % change. This is because the loosing of some molecules and the molecules are entering the water surrounding the vessel also known as diffusion and osmosis

Solutions

Molality

Initial mass(mi)

Final mass

(mf)

Mas difference

(∆m)

% difference=

(∆m/mi)100

Tonicity

A

2m

4.04g

4.12g

0.08g

1.98%

Hypotonic

B

0.4m

4.47g

3.81g

- 0.66g

-14.77%

Hypertonic

C

0.2m

4.92g

4.29g

- 0.63g

-12.80%

Hypertonic

D

0.3m

4.55g

4.15g

- 0.4g

-8.79%

Hypertonic

E

1.1m

3.99g

3.73g

- 0.26g

- 6.51%

Hypotonic

F

0.

3.40g

3.30g

-0.10g

-2.94%

Hypertonic

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