Question

you are doing a research on a space station located on Planet Z. the temp is 29.85 in the space stattion and the air pressure is is 727.6 mm Hg. A ballon with a voulme of 338.9 l inside the space station where the atomospheric pressure is 0.2atm. The voulme of the baloon changes to 575.1 ml. What is the temp

Answer 1

Given : Temp. T₁= 29.85 + 273.15 = 303 K

Pressure P₁ = 727.6 mm Hg = 0.9574 atm

Volume V₁ = 338.9 litre

Temp, T₂ = ?

Pressure P₂ = 0.2 atm

Volume V₂ = 575.1 ml = 0.575 litre

We have relation PV = nRT

Here P₁V₁= n R T₁ --------> 1 and P₂V₂= n R T₂ ---------> 2

Here n is same so dividing equation 1 by equation 2 we get

P₁ V₁ / P₂V₂ = T₁/ T₂

( 0.9574 atm x  338.9 litre / 0.2 atm x 0.575 litre ) = 303 K / T₂

2821.4 = 303 K/ T₂

T₂ = 303K / 2821.4

T₂ = 0.1074 K