Question

The reactions studied in this experiment obey the usual rules of stoichiometry.

Consider the reaction: Mg(NO3)2(aq) + 2 NaOH(aq) --> Mg(OH)2(s) + 2 NaNO3(aq)

To 2.0 mL of 0.10 Mg(NO3)2 in a test tube, 3.0 M NaOH is added dropwise. Calculate the number of mmoles of Mg(No3)2 in the solution. *Note do not use scientific notation.

Answer 1

Mg(NO3)2(aq) + 2 NaOH(aq) --> Mg(OH)2(s) + 2 NaNO3(aq)

1 mole                 2 moles

no of mmoles og Mg(NO3)2 = molarity * volume in ml

                                                = 0.1*2 = 0.2mmoles   = 2*10^-1 mmoles