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What’s the heat of vaporization of acetone (boiling point = 56 °C, vapor pressure at 298...

What’s the heat of vaporization of acetone (boiling point = 56 °C, vapor pressure at 298 K = 30.6 kPa)?

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Answer #1

P2 = 1atm

T2 = 56+273   = 329K

P1 = 30.6KPa = 30.6*0.009869atm   = 0.302atm               [ Kpa = 0.009869atm]

T1 = 298K

logP2/P1   = H/2.303R[1/T1-1/T2]

log1/0.302   = H/2.303*8.314[1/298-1/329]

0.519         = H/19.147 (0.00335-0.00304)

0.519         = H*0.00031/19.147

H          = 0.519*19.147/0.00031   = 32055.78J /mole    = 32KJ/mole >>>>answer

the heat of vaporization of acetone = 32KJ/mole

H            = 0.519*19.147/

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