Question

part a: How many moles of gas does a 1.00 L container is filled with 1.52 atm N₂, 0.12 atm O₂, and 0.040 atm CO₂ gases at 25 °C?

part b: How many moles of N₂ gas are there in a 1.0 L container which contains 1.52 atm of N₂ gas at 25 ºC?

part c: How many moles of O₂ gas are there in a 1.0 L container which contains 0.12 atm of O₂ gas at 25 ºC?

part d:How many moles of CO₂ gas are there in a 1.0 L container which contains 0.040 atm of CO₂ gas at 25 ºC?

Answer 1

part A

from ideal gas equation

PV = nRT

n = PV/RT

    = (1.52+0.12+0.04)*1/(0.0821*298)

n = no of mol of gas mixture = 0.069 mol

part B

n = no of mol of N2 gas

n = PV/RT

    = (1.52)*1/(0.0821*298)

    = 0.062 mol

part C

n = no of mol of O2 gas

n = PV/RT

    = (0.12)*1/(0.0821*298)

    = 0.0049 mol

Part D

n = no of mol of CO2 gas

n = PV/RT

    = (0.04)*1/(0.0821*298)

    = 0.00163 mol