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A possible error can occur in this experiment by having the calorimeter itself absorbs some of...

A possible error can occur in this experiment by having the calorimeter itself absorbs some of the heat from the metal. Does this error make the specific heat value obtained for the metal higher than really is? Or will it be lower? Justify your position

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Answer #1

Heat supplied to the system, Q(say) = heat energy taken by the metal + heat energy absorbed by the calorimeter(Qcalorimeter)

Let C be heat capacity of metal , ΔT be temeperature change of metal. and m is mass of metal.

then Q= mCΔT+ Qcalorimeter

but in our calculations since we take heat absorbed by calorimeter to be zro.

So,Q= mC(actual)ΔT+ Qcalorimeter= mC(metal calculated bus us)ΔT

from this we willl get specific heat capacity of metal C(metal) to be greater than its actual value.

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