Question

Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the unwieldy formula of KHC8H4O4. This is often written in shorthand notation as KHP. If 30.7 mL of a barium hydroxide solution are needed to neutralize 1.18 grams of KHP, what is the molarity of the barium hydroxide solution?

Answer 1

2KHC8H4O4 + Ba(OH)2 --------------> Ba(HC8H4O4)2 + 2KOH

no of moles of KHP   = W/G.M.Wt   = 1.18/204   = 0.00578 moles

2 moles of KHC8H4O4 react with 1 moles of Ba(OH)2

0.00578 moles of KHC8H4O4 react with = 1*0.00578/2   = 0.00289 moles of Ba(OH)2

no of moles of Ba(OH)2 = molarity * volume in L

                0.00289             = molarity * volume in L

molarity                   = 0.00289/0.0307   = 0.094 M >>>>answer