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The concentration of iodide ions in a saturated solution of silver iodide is ________ M. The...

The concentration of iodide ions in a saturated solution of silver iodide is ________ M. The solubility product constant of AgI is 8.3 × 10-17.

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Answer #1

Concentration of Iodide ion in saturated solution of AgI = 9.12×10-9M

Explanation

The solubility equillibrium of AgI written as follows

AgI(s) <--------> Ag+ (aq) + I-(aq)

The equillibrium constant expression for this equillibrium is written as follows

Ksp = [Ag+] [I-]

Where,

[Ag+] = Molarity of Ag+ ions

[I-] = Molarity of I- ions

Ksp of AgI is 8.3×10-17M2

If we put solubility of AgI as S , then

[Ag+] = S

[I-] = S

Therefore,

(S)(S) = 8.3×10-17M2

S2 = 8.3 ×10-17M2

S = 9.12×10-9M

Therefore,

Concentration of Iodide ions in saturated solution of AgI = 9.12×10-9M

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