Question

the respective masses in amu of the proton, the neutron, and the nickel-60 are 1.00728,1.00867 and...

the respective masses in amu of the proton, the neutron, and the nickel-60 are 1.00728,1.00867 and 59.9308. what is the mass defect of the nickel-60 nuclide in amu?

Homework Answers

Answer #1

nickel - 60 contain 28 proton and 32 neutron thus,

theoretical mass of nickel m' = ( 28 mp ) + (32 mn)

= ( 28 1.00728) + (32 1.00867)

= (28.20384) +(32.27744)

= 60.48128 amu

mass defect ( m) = m' - m = 60.48128 - 59.9308 = 0.55048 amu

mass defect of the nickel-60 nuclide is = 0.55048 amu

  

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
You know that: mass of proton (mp) = 1.007276 amu, mass of neutron (mn) = 1.008665...
You know that: mass of proton (mp) = 1.007276 amu, mass of neutron (mn) = 1.008665 amu, and mass of electron (me)= 5.485799 x 10-4 amu. Calculate the mass defect (in amu) and nuclear binding energy (in J/nucleon) for Carbon-12 (nuclear mass: 11.996708 amu)
What is the binding energy of 60 Co (atomic # 27)? The mass of 60 Co...
What is the binding energy of 60 Co (atomic # 27)? The mass of 60 Co is 59.9338 amu, the mass of a proton is 1.00728 amu, and the mass of a neutron is 1.00866 amu.
The average atomic mass of nickel is 58.693 amu. Given the data in the following table,...
The average atomic mass of nickel is 58.693 amu. Given the data in the following table, what is the natural abundance of nickel-64? 58Ni: 57.935 amu 68.0769% abundance 60Ni: 59.931 amu 26.2231% abundance 61Ni: 60.931 amu 1.1399% abundance 62Ni: 61.928 amu 3.6345% abundance 64Ni: 63.928 amu ? % abundance
Where a stationary neutron combines with a proton to form a deuteron, a gamma ray of...
Where a stationary neutron combines with a proton to form a deuteron, a gamma ray of energy 2.2233 MeV is emitted. The masses of the proton and the deuteron are 1.007276467 u and 2.013553212 u, respectively. Determine the mass of the neutron, stating any laws used and defining variables. Ans 1.0087 u
•A beryllium reflector is exposed to a neutron of 1 MeV energy. Assume the masses of...
•A beryllium reflector is exposed to a neutron of 1 MeV energy. Assume the masses of the neutron and the beryllium atom are 1 and 9.01 amu, respectively. Calculate the maximum and average energies transferred from the neutron to the beryllium. please make your writing clear and show steps and write the formula
What percentage of the mass of the isotope magnesium-24 do its neutrons contribute? proton = 1.0073...
What percentage of the mass of the isotope magnesium-24 do its neutrons contribute? proton = 1.0073 amu neutron = 1.0087 amu electron = 5.4858×10-4 amu
The isotopic mass of Rn-210 is 209.989669 amu. When this nuclide decays by electron capture, it...
The isotopic mass of Rn-210 is 209.989669 amu. When this nuclide decays by electron capture, it emits 2.368 MeV. What is the isotopic mass of the resulting nuclide?
The atomic masses of 203Tl and 205Tl are 202.972336 and 204.974410 amu, respectively. The average atomic...
The atomic masses of 203Tl and 205Tl are 202.972336 and 204.974410 amu, respectively. The average atomic mass of thallium is 204.383 amu. Calculate the natural abundances of these two isotoped. Percent abundance of 203Tl: ____% Percent abundance of 205Tl: _____%
An injection containing 13.0 pg 10 5B was injected into a patient suffering from a brain...
An injection containing 13.0 pg 10 5B was injected into a patient suffering from a brain tumor. The patient was irradiated by a neutron gun at the site of the tumor. Calculate the amount of energy released in megaelectronvolts given that 931 MeV is released for each 1 amu mass defect. To calculate the energy released, consider the isotopic masses as follows: Element or particle Isotopic mass (amu) 10 5 B 10.0129 neutron 1.0086 7 3Li 7.0160 alpha particle 4.0026
1. Given the following information: Proton mass = 1.0078 u Neutron mass = 1.0087 u Mass...
1. Given the following information: Proton mass = 1.0078 u Neutron mass = 1.0087 u Mass of 226/88 Ra = 226.0244 u a) Determine the mass defect for this isotope. b) Determine the binding energy for nucleon for this isotope. c) Radium-88 undergoes alpha decay via the following equation: 226/88Ra = 222/86Rn + 4/2He + Q If the mass of the radon-86 isotope is 222.0165 u and the mass of the helium- 4 isotope is 4.0026 u, how much energy,...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT