Question

Aqueous hydrobromic acid HBr will react with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. Suppose 20. g of hydrobromic acid is mixed with 13.1 g of sodium hydroxide. Calculate the maximum mass of sodium bromide that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

Chemical reaction take place as follow

HBr + NaOH NaBr + H₂O

molar mass of NaOH = 39.997 gm/mole that mean 1 mole of NaOH = 39.997gm

molar mass of HBr = 80.91 gm/mole that mean 1 mole of HBr = 80.91gm

According to reaction NaOH and HBr react equimolar proportion

that mean 39.997 gm NaOH react with 80.91 gm HBr then 13.1 gm NaOH require 80.9113.1/39.997 = 26.5 gm of

HBr but it is taken 20 gm so HBr is limiting reactant teact comletly and NaOH is excess reactant remain some amount unreacted.

1 mole of HBr produce 1 mole of NaBr that mean 80.91 gm of HBr produce 102.894 gm(molar mass of NaBr) of NaBr then 20 gm of HBr produce 20102.894/80.91 = 25.434 gm of NaBr

maximum mass of sodium bromide that could be produced = 25.434 gm