Calculate the pH of each solution given the following [H3O+] or [OH−] values.
Part A: [H3O+] = 3×10−4 M
Express your answer using one decimal place.
Part B: [H3O+] = 2×10−9 M
Part C: [OH−] = 4×10−5 M
Part D: [OH−] = 4.5×10−11 M
Part E: [H3O+] = 5.1×10−8 M
Part F: [OH−] = 8.0×10−4 M
A)
we have below equation to be used:
pH = -log [H3O+]
= -log (3*10^-4)
= 3.5
B)
we have below equation to be used:
pH = -log [H3O+]
= -log (2*10^-9)
= 8.7
C)
we have below equation to be used:
pOH = -log [OH-]
= -log (4*10^-5)
= 4.4
we have below equation to be used:
PH = 14 - pOH
= 14 - 4.4
= 9.6
D)
we have below equation to be used:
pOH = -log [OH-]
= -log (4.5*10^-11)
= 10.3
we have below equation to be used:
PH = 14 - pOH
= 14 - 10.3
= 3.7
E)
we have below equation to be used:
pH = -log [H3O+]
= -log (5.1*10^-8)
= 7.3
F)
we have below equation to be used:
pOH = -log [OH-]
= -log (8*10^-4)
= 3.1
we have below equation to be used:
PH = 14 - pOH
= 14 - 3.1
= 10.9
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