Question

For the isomerization of glucose-1-phosphate to glucose-6-phosphate, the ΔG°′ = -7.28 (correct?). [Express your answer in kJ/mol using 2 significant figures.] the tolerance is +/-2%

At 37°C and concentrations of 5 mM glucose-6-phosphate and 0.1 mM glucose-1-phosphate, the ΔG = . [Express your answer in kJ/mol using 2 significant figures.] the tolerance is +/-2%

Under these differing conditions, the isomerization of G1P to G6P is spontaneous under the 25C or 37C?

Phosphoenolpyruvate

Delta G = −61.9

1,3-Bisphosphoglycerate

−49.4

ATP → AMP + PP_i

−45.6

Phosphocreatine

−43.1

ATP → ADP + P_i

−30.5

Glucose-1-phosphate

−20.9

PP_i → 2 P_i

−19.2

Glucose-6-phosphate

−13.8

Glycerol-3-phosphate

 −9.2

Answer 1

A ----------> B

delta G rxn = delta G of B - delta G of A

glucose-1-phosphate ------------> glucose-6-phosphate

delta Grxn = -13.8 - ( -20.9) = 7.1 KJ/mol

From your given data ..i got this but actually

delta Grxn from glucose-1-phosphate ------------> glucose-6-phosphate is -7.28 KJ/mol

It means the delta G values u have given are incorrect

delta G = delta Go + RT lnQ

Q = [ glucose-6-phosphate ] / [ glucose-1-phosphate ] = 5 mm / 0.1 mm = 50

delta G = -7.28 KJ + (8.314*(37+273)* ln50 ) = -2.8 KJ

when delta G is negative the reaction is spontaneous ;

At 25C the delta G value is negative

So the reaction is spontaneous at 25 C (not at 37 C since delta G is +ve )