Question

A silver block, initially at 55.6 ∘C, is submerged into 100.0 g of water at 25.2 ∘C, in an insulated container. The final temperature of the mixture upon reaching thermal equilibrium is 27.3 ∘C. Part A What is the mass of the silver block?

Answer 1

The following formula can be used

Q = mc∆T

Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat (units J/g∙^oC), ∆ is a symbol meaning "the change in"

∆T = change in temperature (^oC Celcius)

Specific Heat Capacity of silver is 0.240 J/g^oC

Specific Heat Capacity of silver is 4.184 J/g^oC

heat lost by silver = heat gained by water

m x 0.24 x (55.6 - 27.3) = 100 x 4.184 x (27.3 - 25.2 )

m x 0.24 x 28.3 = 418.4 x 2.1

m x 0.24 x 28.3 = 878.64

m = 129.363 gm

Hence Mass of the silver = 129.363 gm