Question

Enter your answer in the provided box. Calculate the mass of water produced by the metabolism...

Enter your answer in the provided box.

Calculate the mass of water produced by the metabolism of 73.0 g of glucose (C6H12O6).

C6H12O6 + 6O2

→

6CO2 + 6H2O
Science   Chemistry   
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Homework Answers

Answer #1

Molar mass of C6H12O6 = 6*MM(C) + 12*MM(H) + 6*MM(O)

= 6*12.01 + 12*1.008 + 6*16.0

= 180.156 g/mol

mass of C6H12O6 = 73 g

mol of C6H12O6 = (mass)/(molar mass)

= 73/180.156

= 0.4052 mol

From balanced chemical reaction, we see that

when 1 mol of C6H12O6 reacts, 6 mol of H2O is formed

mol of H2O formed = (6/1)* moles of C6H12O6

= (6/1)*0.4052

= 2.4312 mol

Molar mass of H2O = 2*MM(H) + 1*MM(O)

= 2*1.008 + 1*16.0

= 18.016 g/mol

mass of H2O = number of mol * molar mass

= 2.4312*18.016

= 43.8 g

Answer: 43.8 g

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