When ethanol (CH3CH2OH) is combusted, such as when in a gasoline blend, the following reaction occurs:
2CH3CH2OH(l)+6O2(g)--->4CO2(g)+6H2O(g)
Based on the standard free energies of formation given in the table below, what is the standard free energy change for this reaction?
Substance | ?G?f (kJ/mol) |
CH3CH2OH(l) | -174.9 |
O2(g) | 0 |
CO2(g) | -394.4 |
H2O(g) | -228.6 |
Express your answer to one decimal place and include the appropriate units.
Standard free energy change for the reaction = sum of free energy of products - sum of free energy of reactants
= [4 x -394.4 + 6 x -228.6] - [2 x -174.9 + 6 x 0]
= -2599.4 kJ/mol
Thus, the standard free energy change for this reaction is -2599.4 kJ/mol
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