Question

Calculate the solubility of CuX(Ksp=[Cu2+][X2?]=1.27

Answer 1

Let the solubility of CuX in NaCN = S mol / L

                                CuX Cu²⁺ + X^2-

We know that        NaCN Na⁺ + CN^-

                         K_sp = [Cu²⁺][X^2-]

But there is no common ion.so its solubility is calculated as follows:

Concentration of Cu²⁺ = S mol / L

Concentration of X^2- = S mol / L

Plug the values we get       K_sp = [Cu²⁺][X^2-]

                                           K_sp = S x S

                                                 = S²

So S = (K_sp ) ^1/2

        = ( 1.27