H3C6H5O7 + 3NaOH --------------- Na3C6H5O7 +3 H2O
1 mole 3 mole
According to equation ,
for 3 moles of NaOH = 1 mole of H3C6H5O7
0.00343 moles of NaOH= ?
= 0.00343 x1/3 = 0.00114 moles fo citric acid
number of moles of citric acid = 0.00114 moles
volume of citric acid = 16.41 ml = 0.01641L
molarity = number of moles/volume in L
= 0.00114/0.0164
=0.0695 M
molarity of NaOH = 0.0695M
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