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Determine the rate law, including the values of the orders and rate law constant, for the...

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided.

Q + X --> products

Trial [Q] [X] Rate
1 0.12 M 0.10 M 1.5 x 10-3 M/min
2 0.24 M 0.10 M 3.0 x 10-3 M/min
3 0.12 M 0.20 M 1.2 x 10-2 M/min
Science   Chemistry   
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Homework Answers

Answer #1

see experiment 1 and 2:

[Q] doubles

[X] is constant

rate doubles

so, order of Q is 1

see experiment 1 and 3:

[Q] is constant

[X] doubles

rate becomes 8 times

so, order of X is 3

overall order = 1 + 3 = 4

Rate law is:

rate = k*[Q]*[X]^3

Put values from 1st row of table in rate law

rate = k*[Q]*[X]^3

1.5*10^-3 = k*0.12*0.1^3

k = 12.5 M-3.s-1

rate = k*[Q]*[X]^3

k = 12.5 M-3.min-1

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