Question

1-Why, in the standardization of H2SO4 with Na2CO3 solution, is titration carried out to pH 4.3...

1-Why, in the standardization of H2SO4 with Na2CO3 solution, is titration carried out to pH 4.3 (methyl orange endpoint) rather than to pH 8.3 (phenolphthalein endpoint)?

2-For each of the solutions titrated, why are the concentrations of OH-, CO32-, and HCO3- somewhat different from those which were indicated on the sample designations?

3-At what pH do the phenolphthalein and methyl orange endpoints occur for the sample for which the titration curve was determined? Compare the equivalence points (inflection points of curves) with the commonly used endpoints of pH 8.3 and 4.3 and explain any difference.

Homework Answers

Answer #1

1)

Titration equations:

Step-1: H2SO4 (aq) + Na2CO3 (aq)   ------> NaHSO4 (aq) + NaHCO3 (aq)  

Step-2: NaHSO4 (aq) + NaHCO3 (aq) -----> Na2SO4 (aq) + H2CO3 (aq)

In the first step, carbonate is converted into bicarbonate. So, the phenolphthalein is suitable for this step.

In second step, bicarbonate is converted into carbonic acid. So, the methyl orange is suitable for this step.

Phenolphthalein is a basic indicator that acts at a pH range of 8-10 whereas methyl orange is an acidic indicator that acts at a pH rang of 4-5.

In the standardization of H2SO4, we known the required volume of sodium carbonate to complete the two steps.

So, the methyl orange is used instead of phenolphthalein.

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