Question

How much of the precipitant will be formed when you react 85.5g of Calcium Nitrate with 85.5g of Lithium Sulfate?

Answer 1

THe balanced equation for the reaction is as :

Li₂SO₄ + Ca(NO₃)₂ = CaSO₄ + 2 LiNO₃

Here the precipitate will be CaSO₄ .

MOlar mass of Lithium Sulfate = 109,94 g/mol

MOlar mass of Calcium Nitrate = 164,088 g/mol

Here calcium nitrate = 85.5g / 164,088 g/mol = 0.522 moles

Here Lithium Sulfate = 85.5g / 109,94 g/mol = 0.778 moles

Here one mole of calcium nitrate reacts with one mole of Lithium Sulfate and produce one mole of calcium sulphate.

So here 0.522 moles of calcium sulphate will be produced.

Molar mass of calcium sulphate = 136,14 g/mol

So, precipitant will be formed = 0.522 moles X (136,14 g/mol) = 71.065 g.