Use the half reactions and standard reduction potentials provided below to calculate the ΔGo’ of: lactate + NAD+ → Pyruvate + NADH + H+ NAD+ + H+ + 2e- → NADH (Eo’ = -0.320 V) lactate → pyruvate + 2H+ + 2e- (Eo’ = 0.185 V) Answer: 26.10 kJ/mol
Please explain steps
NAD+ + H+ + 2e- → NADH Eo’ = -0.320 V
lactate → pyruvate + 2H+ + 2e- Eo’ = 0.185 V
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lactate + NAD+ -------------> pyruvate + NADH + H+
Eocell = Eored - Eooxidation
Eo = - 0.320 + 0.185
= - 0.135 V
ΔGo = - n F Eo
= - 2 x 96500 x - 0.135 x 10^-3
ΔGo = 26.10 kJ /mol
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