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A sample containing 42.9 g of Ar is enclosed in a container of volume 8.05×10−2 L...

A sample containing 42.9 g of Ar is enclosed in a container of volume 8.05×10−2 L at 375 K.

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Answer #1

Molar mass of Ar = 39.95 g/mol

mass of Ar = 42.9 g

we have below equation to be used:

number of mol of Ar,

n = mass of Ar/molar mass of Ar

=(42.9 g)/(39.95 g/mol)

= 1.074 mol

we have:

V = 0.0805 L

n = 1.0738 mol

T = 375.0 K

we have below equation to be used:

P * V = n*R*T

P * 0.0805 L = 1.0738 mol* 0.0821 atm.L/mol.K * 375 K

P = 411 atm

Answer: 411 atm

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