A standard solution is prepared for the analysis of fluoxymesterone (C20H29FO3), an anabolic steroid.
A stock solution is first prepared by dissolving 10.0 mg of fluoxymesterone in enough water to give a total volume of 500.0 ml.
A 100.0 μL aliquot (portion) of this solution is diluted to a final volume of 100.0 ml.
Calculate the concentration of the final solution in terms of molarity
Molar mass of C20H29FO3 = 336.44 g/mol
Given : A stock solution is
first prepared by dissolving 10.0 mg of fluoxymesterone in enough
water to give a total volume of 500.0 mL
Therefore, moles of fluoxymesterone = 10.0 x
10-3 g / 336.441 g/mol = 0.0000297
1L = 1000mL
Initial concentration of fluoxymesterone = 0.0000297 / 0.500 L=0.0000594
100 microliter = 0.000100
L
Now the moles of fluoxymesterone = 0.0000594 x 0.000100 L = 5.94 x
10-8
New concentration of fluoxymesterone = 5.94 x 10-8 /
0.100 L = 5.94 x 10-7 M
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