Question

For the reaction, calculate how many moles of the product form
when 0.046 mol of O2 completely reacts.

Assume that there is more than enough of the other reactant.

2Ca(*s*)+O2(*g*)→2CaO(*s*)

For the reaction, calculate how many moles of the product form
when 0.018 mol of O2 completely reacts.

Assume that there is more than enough of the other reactant.

4Fe(*s*)+3O2(*g*)→2Fe2O3(*s*)

For the reaction, calculate how many moles of the product form
when 0.044 mol of K completely reacts.

Assume that there is more than enough of the other reactant.

4K(*s*)+O2(*g*)→2K2O(*s*)

For the reaction, calculate how many moles of the product form
when 0.036 mol of O2 completely reacts.

Assume that there is more than enough of the other reactant.

4Al(*s*)+3O2(*g*)→2Al2O3(*s*)

Answer #1

1)

from given reaction,

mol of CaO = 2*moles of O2 reacting

= 2*0.046 moles

= 0.092 moles

Answer: 0.092 moles

2)

from given reaction,

mol of Fe2O3 = (2/3)*moles of O2 reacting

= (2/3)*0.018 moles

= 0.012 moles

Answer: 0.012 moles

3)

from given reaction,

mol of K2O = (2/4)*moles of K reacting

= (2/4)*0.044 moles

= 0.022 moles

Answer: 0.022 moles

4)

from given reaction,

mol of Al2O3 = (2/3)*moles of O2 reacting

= (2/3)*0.036 moles

= 0.024 moles

Answer: 0.024 moles

For the reaction below, calculate how many moles of the product
form when 0.026 mol of O2 completely reacts. Assume that there is
more than enough of the other reactant.
2Ca(s)+O2(g)→2CaO(s)
Express your answer using two significant figures.

For the reaction, calculate how many grams of the product form
when 24.4 g of O2 completely reacts.
Assume that there is more than enough of the other reactant.
4Cr(s)+3O2(g)→2Cr2O3(s)

(Part A) For the reaction, calculate how many grams of the
product form when 16.4 g of O2 completely reacts.
Assume that there is more than enough of the other reactant.
4Cr(s)+3O2(g)→2Cr2O3(s)
(Part B) For the reaction, calculate how many grams of the
product form when 16.4 g of Sr completely reacts.
Assume that there is more than enough of the other reactant.
2Sr(s)+O2(g)→2SrO(s)

(Part A) For the reaction, calculate how many grams of the
product form when 16.4 g of Ca completely reacts.
Assume that there is more than enough of the other reactant.
Ca(s)+Cl2(g)→CaCl2(s)
(Part B) For the reaction, calculate how many grams of the
product form when 16.4 g of Br2 completely reacts.
Assume that there is more than enough of the other reactant.
2K(s)+Br2(l)→2KBr(s)

For each of the reactions, calculate the mass (in grams) of the
product formed when 3.30 g of the underlined reactant completely
reacts. Assume that there is more than enough of the other
reactant.
(underlined)
Ba(s)?????+Cl2(g)?BaCl2(s)
(underlined)
CaO(s)??????+CO2(g)?CaCO3(s)
(underlined)
2Mg(s)?????+O2(g)?2MgO(s)
(underlined)
4Al(s)?????+3O2(g)?2Al2O3(s)

For each of the reactions, calculate the mass (in grams) of the
product formed when 3.33 g of the underlined reactant completely
reacts. Assume that there is more than enough of the other
reactant.
1. Ba(s)+Cl2(g)→BaCl2(s)
2. CaO(s)+CO2(g)→CaCO3(s)
3. 2Mg(s)+O2(g)→2MgO(s)
4. 4Al(s)+3O2(g)→2Al2O3(s)

For the reaction shown, calculate how many moles of NO2 form
when each amount of reactant completely reacts.
2N2O5(g)→4NO2(g)+O2(g)
a. 6.4 mol N2O5
b. 10.0 g N2O5
c. 1.55 kg N2O5

For the reaction shown, calculate how many grams of each product
form when the following amounts of reactant completely react to
form products. Assume that there is more than enough of the other
reactant. 2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(l)
A.) 4.0 gFe2O3

CaO(s)−−−−−−+CO2(g)→CaCO3(s)
Express your answer using two significant figures.
For each reaction, calculate the mass (in grams) of the product
formed when 2.9 g of the underlined reactant completely reacts.
Assume that there is more than enough of the other reactant.
Ba(s)−−−−−+Cl2(g)→BaCl2(s)
Express your answer using two significant figures.
2Mg(s)−−−−−+O2(g)→2MgO(s)
Express your answer using two significant figures.
4Al(s)−−−−−+3O2(g)→2Al2O3(s)
Express your answer using two significant figures.

grams A to moles A to moles B to grams B 2 C4H10 (l) + 13 O2(g)
--> 8 CO2(g) + 10 H2O(g) How many moles of each product will
form if 8.12 g of butane (C4H10) reacts completely to form
products? Assume there is more than enough of the other reactant.
How many grams of CO2 will form?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 10 minutes ago

asked 14 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago