Is the heat/mol rxn value for the reaction of CH3COOH + OH- any different than the value for CH3COOH(aq) + NaOH(aq)? Explain.
Standard enthalpy of neutralization (heat of reaction of acid-base reaction) is the amount of energy produced when an acid and base reacts to produce 1 mol of water molecules.
Order of heat of reaction: (strong acid- strong base) > (Strong acid-weak base) = (Weak acid-strong base) > (weak acid- weak base).
Reaction 1: CH3COOH + OH- ----------> dH(rxn1)
Reaction 2: CH3COOH + Na+OH- ------> dH(rxn2)
Case 1: dH(rxn1) = dH(rxn2) ; if OH- comes from a strong base similar to NaOH.
Case 2: dH(rxn1) < dH(rxn2) ; if OH- comes from a weak base like H2O or alcohol, etc.
Carboxylic acids are weak acid. Heat of neutralization of carboxylic acid and strong base (here, NaOH) is larger than that of carboxylic acid and weak base (like H2O and alcohol).
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