A sample of K 3 P O 4 ( molar mass = 212.27 g/mol) contain s 1.5 24 ×10 24 potassium ions. What is the mass, in grams, of the potassium phosphate sample? ***Please Explain***
number of K+ = 1.524*10^24 ions
1 molecule of K3PO4 has 3 K+
So,
molecules of K3PO4 = number of K+ / 3
= 1.524*10^24)/3
= 5.08*10^23 molecules
we have below equation to be used:
number of mol = number of molecules / Avogadro’s number
number of mol = 5.08*10^23 / 6.022*10^23 mol
number of mol = 0.8436 mol
Molar mass of K3PO4 = 212.27 g/mol
we have below equation to be used:
mass of K3PO4,
m = number of mol * molar mass
= 0.8436 mol * 212.27 g/mol
= 1.791*10^2 g
Answer: 179.1 g
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