Question

Constant-boiling HCl can be used as a primary standard for acid-base titrations. A 50.00 mL sample of constant-boiling HCl with a concentration of 0.1251 M was collected and titrated to an end point with 33.37 mL of Ba(OH)2 solution. What is the molarity of the Ba(OH)2 solution?

Answer 1

concentration of HCL= 0.1251 M

means 0.1251 moles present in1000 ml

so by unitary method no of moles in 50 ml = (0.1251/1000)*(50) =6.255* 10^-3

according to reaction

2HCl + Ba(OH)2 ---------------> Ba(Cl)2 + 2 H2O

means 2 mole of HCL is required for 1 mole of Ba(OH)2

so at neutral point , no of mole of Ba(OH)2 are 1/2 of HCL

no of mole of Ba(OH)2 = 6.255*10^-3/2 = 3.1275*10^-3

now molarity

3.1275*10^-3 in 33.37 ml .

so in 1000 ml =(3.1275*10^-3/33.37)*1000

=0.09477 M

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