Question

In the reaction NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq) 1. How many milliliters of 0.165 M NaOH are needed to react...

In the reaction
NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq)

1. How many milliliters of 0.165 M NaOH are needed to react with 21.9 mL of 0.465 MNiCl2?

2. How many grams of Ni(OH)2 are produced from the reaction of 34.9 mL of 1.87 MNaOH?

Homework Answers

Answer #1

In the given reaction,

NiCl2 + 2NaOH --> Ni(OH)2 + 2NaCl

1 mol of NiCl2 reacts with 2 mols of NaOH

1. mols of NiCl2 present = 0.465 M x 21.9 ml = 10.1835 mmol

mols of NaOH neede = 2 x 10.1835 = 20.367 mmol

Volume of NaOH needed = 20.367 mmol/0.165 M = 123.44 ml

2. mols of NaOH used = 1.87 M x 34.9 ml = 65.263 mmol

mols of Ni(OH)2 produced = 65.263 mmol/2 = 32.6315 mmol

grams of Ni(OH)2 produced = 32.6315 mmol x 92.708 g/mol/1000 = 3.025 g

[Formulas used, molarity = moles/L of solution ; moles = grams/molar mass]

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
n the reaction NiCl2(aq) + 2NaOH(aq) → Ni(OH)2(s) + 2NaCl(aq) How many milliters (mL) of 0.836...
n the reaction NiCl2(aq) + 2NaOH(aq) → Ni(OH)2(s) + 2NaCl(aq) How many milliters (mL) of 0.836 M NaOH are needed to react with 12.8 mL of 0.500 M NiCl2?
How many grams of Ni(OH)2 are produced from the reaction of 30.5 mL of 1.87 M...
How many grams of Ni(OH)2 are produced from the reaction of 30.5 mL of 1.87 M NaOH? NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq)
(a) How many milliliters of 0.165 M HCl are needed to neutralize completely 35.0 mL of...
(a) How many milliliters of 0.165 M HCl are needed to neutralize completely 35.0 mL of 0.101 M Ba(OH)2 solution? ________ ml (b) How many milliliters of 2.50 M H2SO4 are needed to neutralize 50.0 g of NaOH? _________ mL (c) If 56.8 mL of BaCl2 solution is needed to precipitate all the sulfate in a 544 mg sample of Na2SO4 (forming BaSO4), what is the molarity of the solution? _________M (d) If 47.5 mL of 0.250 M HCl solution...
(a) How many milliliters of 0.165 M HCl are needed to neutralize completely 35.0 mL of...
(a) How many milliliters of 0.165 M HCl are needed to neutralize completely 35.0 mL of 0.101 M Ba(OH)2 solution? ______ml (b) How many milliliters of 3.50 M H2SO4 are needed to neutralize 75.0 g of NaOH? _______mL (c) If 55.8 mL of BaCl2 solution is needed to precipitate all the sulfate in a 544 mg sample of Na2SO4 (forming BaSO4), what is the molarity of the solution? ________M (d) If 47.5 mL of 0.375 M HCl solution is needed...
How many milliliters of 0.215 M FeCl3 solution are needed to react completely with 32.7 mL...
How many milliliters of 0.215 M FeCl3 solution are needed to react completely with 32.7 mL of 0.0509 M AgNO3 solution? The net ionic equation for the reaction is: Ag+(aq) + Cl-(aq) AgCl(s) mL of FeCl3: How many grams of AgCl will be formed?
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of...
Calculate how many milliliters of 1 M NaOH will be needed to make 1 L of 0.1 M solution. Calculate how many grams of potassium acid phthalate (KHP, FW = 204.2 g/mol) will react with about 25 ml of the 0.1 M NaOH solution. The reaction is as follows: HKC8H4O4 + NaOH → H2O + NaKC8H4O4 Calculate how many mL of 1 M HCl is needed to make 1 L of 0.2 M HCl. HCl + NaOH → H2O +...
How many grams of NaH2PO4 are needed to react with 30.66 mL of 0.260 M NaOH?...
How many grams of NaH2PO4 are needed to react with 30.66 mL of 0.260 M NaOH? NaH2PO4(s) + 2 NaOH(aq) → Na3PO4(aq) + 2 H2O(l)
How many grams of NaH2PO4 are needed to react with 32.94 mL of 0.280 M NaOH?...
How many grams of NaH2PO4 are needed to react with 32.94 mL of 0.280 M NaOH? NaH2PO4(s) + 2 NaOH(aq) Na3PO4(aq) + 2 H2O(l)
Enter your answer in the provided box. How many grams of NaH2PO4 are needed to react...
Enter your answer in the provided box. How many grams of NaH2PO4 are needed to react with 26.93 mL of 0.391 M NaOH? NaH2PO4(s) + 2NaOH(aq) → Na3PO4(aq) + 2H2O(l)
Write the complete ionic and the net ionic equations. BaCl2(aq)+2NaIO3(aq)➡Ba(IO3)2(aq)+2NaCl (aq) 2NaOH(aq)+BaCl2(aq)➡Ba(OH)2(s)+2NaCl(aq)
Write the complete ionic and the net ionic equations. BaCl2(aq)+2NaIO3(aq)➡Ba(IO3)2(aq)+2NaCl (aq) 2NaOH(aq)+BaCl2(aq)➡Ba(OH)2(s)+2NaCl(aq)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT