Question

Calculate the radius of iridium atom, given that Ir has an FFC crystal structure, a density...

Calculate the radius of iridium atom, given that Ir has an FFC crystal structure, a density of 22.4 g/cm3 and atomic weight of 192.2g/mol.

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

d = ZM/Na^3

in FCC no of atoms 4 in unit cell z = 4

M = 192.2g/mole

d = 22.4g/cm^3

N = 6.023*10^23

d = ZM/Na^3

22.4 = 4*192.2/6.023*10^23 * a^3

a^3   = 4*192.2/6.023*10^23*22.4

a^3   = 5.7*10^-23

a    = 3.8*10^-8 cm

for FCC

a = 22 r

3.8*10^-8 = 2*1.414*r

r              = 3.8*10^-8/2.828    = 1.34*10^-8cm

The radius of iridium atom = 1.34*10^-8cm = 1.34A0 >>>>answer

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Calculate the radius of an silver atom in cm, given that Ag has an FCC crystal...
Calculate the radius of an silver atom in cm, given that Ag has an FCC crystal structure, a density of 10.5 g/cm3, and an atomic weight of 107.87 g/mol.
Calculate the theoretical density of an unidentified atom that has an HCP crystal structure if the...
Calculate the theoretical density of an unidentified atom that has an HCP crystal structure if the lattice constants are a = 300 pm and c = 450 pm. Atomic weight of the atom is 45.2 g/mol. Avogadro's number = 6.023 x 1023 atoms/mole.
BCC (body-centered cubic) crystal structure is one of common crystal structuresfor metals. Please do the following...
BCC (body-centered cubic) crystal structure is one of common crystal structuresfor metals. Please do the following questions. (a) Describe what is a BCC structure and draw a BCC unit cell. (b) Calculate the radius of a vanadium (V) atom, given that V has a BCCcrystal structure, a density of 5.96 g/cm3, and an atomic weight of 50.9 g/mol.
1) For a metal that has the face-centered cubic (FCC) crystal structure, calculate the atomic radius...
1) For a metal that has the face-centered cubic (FCC) crystal structure, calculate the atomic radius if the metal has a density of (8.000x10^0) g/cm3 and an atomic weight of (5.80x10^1) g/mol.  Express your answer in nm. 2) Consider a copper-aluminum solid solution containing (7.82x10^1) at% Al. How many atoms per cubic centimeter (atoms/cm^3) of copper are there in this solution? Take the density of copper to be 8.94 g/cm3 and the density of aluminum to be 2.71 g/cm3.
The very dense metal iridium has a face centered cubic structure and density of 22.56 g/cm3....
The very dense metal iridium has a face centered cubic structure and density of 22.56 g/cm3. use this information to calculate the radius of an iridium atom.
The density of a uniform crystal structure can be estimated from the crystal type and information...
The density of a uniform crystal structure can be estimated from the crystal type and information about the lattice parameter and atomic radii. Estimate the density of a material (gram/cm3) for a material with these properties: Atomic Radius = 0.1281 nm Crystal Type = FCC atomic Mass = 47 grams/mol (Note: Avogadro's Number , 6.022x10^23 atoms/mol)
Iridium packs in a face centered cubic structure with a density of 22.43 g/cm3 . Calculate...
Iridium packs in a face centered cubic structure with a density of 22.43 g/cm3 . Calculate the following: (1) Volume of unit cell in pm3 . (2) cell length (3) radius of iridium.
iridium has a cubic closest packed structure with an edge length of 385 pm. calculate the...
iridium has a cubic closest packed structure with an edge length of 385 pm. calculate the value of the atomic radius and the density of iridium
Hetero atom (1) calculate radius of atom which forms simple cubic crystal structure. Lattice constant=4.0Å (2)...
Hetero atom (1) calculate radius of atom which forms simple cubic crystal structure. Lattice constant=4.0Å (2) calculate radius of atom which forms HCP crystal structure. Lattice constant a=3.0Å (3) calculate nuclear distance of body-centered tetragonal(Lattice constant a=b=5Å, c=6Å), and atomic packing factor.
Below are listed the atomic weight, density, and atomic radius for three hypothetical alloys at room...
Below are listed the atomic weight, density, and atomic radius for three hypothetical alloys at room temperature. For each determine whether its crystal structure is FCC, BCC, or simple cubic and then justify your answer. Alloy Atomic weight Density Atomic radius (g/mol) (g/cm3) (nm) A 195.08 21.45 0.139 B 209 9.32 0.335 C 55.85 7.87 0.124
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT