Question

Using a thermodynamic table below , determine the bond energy of F2, along with the fraction of diatomics that have sufficient energy to react at 298K and 500K.

	ΔH°f (kJ mol-1)	ΔG°f (kJ mol-1)	S°m (J mol-1 K-1)	Cp,m (J mol-1 K-1)	Molecular weight
F2(g)	0	0	202.8	31.3	38.00
F(g)	79.4	62.3	158.8	22.7	19.00

Answer 1

2 F -> F2

at 298 K

K=0.144

at 500 K

K=0.22

data point 1

(0.16, 298 K)

data point 2

(0.22, 500K)
slpoe of line with these data points where y coordinate is ln(K) and x coordinate is 1/T = 236.04

activation energy/R = 236.04

fraction of diatomics that have sufficient energy to react at 298K =

=

=0.45 = action of diatomics that have sufficient energy to react at 298K

at 500 K

=

0.623= action of diatomics that have sufficient energy to react at 500 K