Question

In run 1, you mix 8.0 mL of the 43 g/L MO solution (MO molar mass is 327.33 g/mol), 3.32 mL of the 0.040 M SnCl2 in 2.0 M HCl solution, 5.30 mL of 2.0 M HCl solution, and 3.39 mL of 2.0M NaCl solution.

What is the [H3O+]? Remember that there is a contribution of H3O+ from two solutions.

Answer 1

mmoles of HCl = 5.30 x 2.0 = 10.6

concentration of [HCl]= 10.6 / 8 + 3.32 + 5.30 + 3.39

                                       = 10.6 / 20.01

                                        = 0.5297 M

[HCl] = 2 x 3.32 / 20.01 = 0.332 M

[H3O+] = 0.332 + 0.5297

[H3O+] = 0.86 M