Question

The gas of2 can be produced from the electrolysis of an aqueous solution KF as shown in the equation below OF2+2H+(aq)+4e-

Answer 1

OF2(g) + 2H+(aq) + 4e ---> H2O(l) + 2F-(aq) Eo= +2.15 V

From the given equation

4 moles of electrons produces 1 mole of OF2 gas

1 mole of electrons carries charge of 1 Faraday (1F = 96500 C)

4 moles of electrons carries = 4F

4F charge produces 1 mole of OF2 gas

For example

IF they pass 0.480 faradays through solution

4F ---> 1mole of OF2

0.48 F --> 1*0.48 / 4 = 0.12 mole of OF2 gas

1 mole of OF2 gas = 54 gm

0.12 moles of OF2 = 54*0.12 = 6.48 gms

IT means 6.48 gms of OF2 is produced